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3 and 4 .Determinants and Matrices
easy
यदि $\Delta = \left| {\,\begin{array}{*{20}{c}}x&y&z\\p&q&r\\a&b&c\end{array}\,} \right|,$ तो $\left| {\,\begin{array}{*{20}{c}}x&{2y}&z\\{2p}&{4q}&{2r}\\a&{2b}&c\end{array}\,} \right|$ का मान होगा
A
${\Delta ^2}$
B
$4\Delta $
C
$3\Delta $
D
इनमें से कोई नहीं
Solution
(b) माना ${\Delta _1} = \left| {\,\begin{array}{*{20}{c}}x&{2y}&z\\{2p}&{4q}&{2r}\\a&{2b}&c\end{array}\,} \right|$=$4\,\left| {\,\begin{array}{*{20}{c}}x&y&z\\p&q&r\\a&b&c\end{array}\,} \right| = 4\Delta $.
($R_2$ तथा $C_2$ से $'2'$ उभयनिष्ठ लेने पर)
Standard 12
Mathematics