3 and 4 .Determinants and Matrices
easy

If $\omega $ is a cube root of unity and $\Delta = \left| {\begin{array}{*{20}{c}}1&{2\omega }\\\omega &{{\omega ^2}}\end{array}} \right|$, then ${\Delta ^2}$ is equal to

A

$ - \omega $

B

$\omega $

C

$1$

D

${\omega ^2}$

Solution

(b) Since $\Delta = {\omega ^2} – 2{\omega ^2} = – {\omega ^2}$.

Therefore ${\Delta ^2} = {\omega ^4} = \omega $.

Standard 12
Mathematics

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