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3 and 4 .Determinants and Matrices
normal
If $A$ and $B$ are two matrices and $(A + B)(A - B)$$ = {A^2} - {B^2}$, then
A
$AB = BA$
B
${A^2} + {B^2} = {A^2} - {B^2}$
C
$A'B' = AB$
D
None of these
Solution
(a) Since $(A + B)(A – B) = {A^2} – {B^2}$
By matrix distribution law,
==> ${A^2} – AB + BA – {B^2} = {A^2} – {B^2}$
==> $BA – AB = 0\,\, \Rightarrow BA = AB$.
Standard 12
Mathematics