3 and 4 .Determinants and Matrices
normal

यदि $A$ और $B$ दो आव्यूह हैं तथा $(A + B)(A - B)$ $ = {A^2} - {B^2}$, तो

A

$AB = BA$

B

${A^2} + {B^2} = {A^2} - {B^2}$

C

$A'B' = AB$

D

इनमें से कोई नहीं

Solution

चूँकि $(A + B)(A – B) = {A^2} – {B^2}$ 

आव्यूह के बंटन नियम से,

==> ${A^2} – AB + BA – {B^2} = {A^2} – {B^2}$   

==> $BA – AB = 0\,\, \Rightarrow BA = AB$.

Standard 12
Mathematics

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