3 and 4 .Determinants and Matrices
easy

यदि $X = \left[ {\begin{array}{*{20}{c}}3&{ - 4}\\1&{ - 1}\end{array}} \right]$, तो ${X^n}$ का मान है

A

$\left[ {\begin{array}{*{20}{c}}{3n}&{ - 4n}\\n&{ - n}\end{array}} \right]$

B

$\left[ {\begin{array}{*{20}{c}}{2 + n}&{5 - n}\\n&{ - n}\end{array}} \right]$

C

$\left[ {\begin{array}{*{20}{c}}{{3^n}}&{{{( - 4)}^n}}\\{{1^n}}&{{{( - 1)}^n}}\end{array}} \right]$

D

इनमें से कोई नहीं

Solution

$X = \left[ {\begin{array}{*{20}{c}}3&{ – 4}\\1&{ – 1}\end{array}} \right] \Rightarrow {X^2} = \left[ {\begin{array}{*{20}{c}}5&{ – 8}\\2&{ – 3}\end{array}} \right]$.       

 स्पष्टत: $n = 2$ के लिए विकल्प $(a), (b), (c)$ में दिये गए आव्यूह, $\left[ {\begin{array}{*{20}{c}}5&{ – 8}\\2&{ – 3}\end{array}} \right]$ से मेल नहीं खाते हैं।

Standard 12
Mathematics

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