3 and 4 .Determinants and Matrices
easy

यदि $A = \left[ {\begin{array}{*{20}{c}}4&{x + 2}\\{2x - 3}&{x + 1}\end{array}} \right]$ सममित है,  तो  $x =$

A

$3$

B

$5$

C

$2$

D

$4$

Solution

चूँकि दिया गया आव्यूह सममित है, इसलिए

 ${a_{12}} = {a_{21}} \Rightarrow x + 2 = 2x – 3 \Rightarrow x = 5$.

Standard 12
Mathematics

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