If A = left[ {begin{array}{*{20}{c}}4&{x + 2}{2x - 3}&{x + 1}end{array}} right] is symmetric

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3 and 4 .Determinants and Matrices

easy

If $A = \left[ {\begin{array}{*{20}{c}}4&{x + 2}\\{2x - 3}&{x + 1}\end{array}} \right]$is symmetric, then $ x =$

A

$3$

B

$5$

C

$2$

D

$4$

Solution

(b) Since the given matrix is symmetric, therefore

${a_{12}} = {a_{21}} \Rightarrow x + 2 = 2x – 3 \Rightarrow x = 5$.

Standard 12

Mathematics

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