3.Trigonometrical Ratios, Functions and Identities
medium

If $\tan \theta = \frac{{ - 4}}{3},$ then $\sin \theta = $

A

$-4/5$ but not $4/5$

B

$-4/5 $ or $4/5$

C

$4/5$ but not $-4/5$

D

None of these

(IIT-1979)

Solution

(b) Since ${\rm{cose}}{{\rm{c}}^2}\theta = 1 + {\cot ^2}\theta = 1 + \frac{9}{{16}} = \frac{{25}}{{16}}$

$\left( \because   {\tan \theta  =  – \frac{4}{3}} \right)$

${\sin ^2}\theta = \frac{1}{{{\rm{cose}}{{\rm{c}}^2}\theta }} = \frac{{16}}{{25}} $

$\Rightarrow \sin \theta = \pm \frac{4}{5},$ 

Both the values are acceptable, since $\tan \theta = – \frac{4}{3}\,\,$ 

$\,i.e.,\theta $ lies in ${2^{nd}}$ or ${4^{th}}$ quadrant.

Standard 11
Mathematics

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