If $2\tan A = 3\tan B,$ then $\frac{{\sin 2B}}{{5 - \cos 2B}}$ is equal to
If $2\tan A = 3\tan B,$ then $\frac{{\sin 2B}}{{5 - \cos 2B}}$ is equal to
- A
$\tan A - \tan B$
- B
$\tan (A - B)$
- C
$\tan (A + B)$
- D
$\tan (A + 2B)$
Similar Questions
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- [JEE MAIN 2021]