If $2\tan A = 3\tan B,$ then $\frac{{\sin 2B}}{{5 - \cos 2B}}$ is equal to

  • A

    $\tan A - \tan B$

  • B

    $\tan (A - B)$

  • C

    $\tan (A + B)$

  • D

    $\tan (A + 2B)$

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