If $a{\sin ^2}x + b{\cos ^2}x = c,\,\,$$b\,{\sin ^2}y + a\,{\cos ^2}y = d$ and $a\,\tan x = b\,\tan y,$ then $\frac{{{a^2}}}{{{b^2}}}$ is equal to

  • A

    $\frac{{(b - c)\,\,(d - b)}}{{(a - d)\,\,(c - a)}}$

  • B

    $\frac{{(a - d)\,\,(c - a)}}{{(b - c)\,\,(d - b)}}$

  • C

    $\frac{{(d - a)\,\,(c - a)}}{{(b - c)\,\,(d - b)}}$

  • D

    $\frac{{(b - c)\,\,(b - d)}}{{(a - c)\,\,(a - d)}}$

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