જો $a{\sin ^2}x + b{\cos ^2}x = c,\,\,$$b\,{\sin ^2}y + a\,{\cos ^2}y = d$ અને $a\,\tan x = b\,\tan y,$ તો $\frac{{{a^2}}}{{{b^2}}} = . . ..$
જો $a{\sin ^2}x + b{\cos ^2}x = c,\,\,$$b\,{\sin ^2}y + a\,{\cos ^2}y = d$ અને $a\,\tan x = b\,\tan y,$ તો $\frac{{{a^2}}}{{{b^2}}} = . . ..$
- A
$\frac{{(b - c)\,\,(d - b)}}{{(a - d)\,\,(c - a)}}$
- B
$\frac{{(a - d)\,\,(c - a)}}{{(b - c)\,\,(d - b)}}$
- C
$\frac{{(d - a)\,\,(c - a)}}{{(b - c)\,\,(d - b)}}$
- D
$\frac{{(b - c)\,\,(b - d)}}{{(a - c)\,\,(a - d)}}$
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