If frac{x}{{cos theta }} = frac{y}{{cos left( | vedclass

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(b) We have $\frac{x}{{\cos 	heta }} = \frac{y}{{\cos \left( {	heta - \frac{{2\pi }}{3}} ight)}} = \frac{z}{{\cos \left( {	heta + \frac{{2\pi }}{

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(b) We have $\frac{x}{{\cos 	heta }} = \frac{y}{{\cos \left( {	heta - \frac{{2\pi }}{3}} ight)}} = \frac{z}{{\cos \left( {	heta + \frac{{2\pi }}{3}} ight)}} = k$

==> $x = k\cos 	heta $, $y = k\cos \left( {	heta - \frac{{2\pi }}{3}} ight)$,

$z = k\cos \left( {	heta + \frac{{2\pi }}{3}} ight)$ 

==> $x + y + z = k\left[ {\cos 	heta + \cos \left( {	heta - \frac{{2\pi }}{3}} ight) + \cos \left( {	heta + \frac{{2\pi }}{3}} ight)} ight]$

$ = k[(0) = 0$ 

$ \Rightarrow $ $x + y + z = 0$.

If $\frac{x}{{\cos \theta }} = \frac{y}{{\cos \left( {\theta - \frac{{2\pi }}{3}} \right)}} = \frac{z}{{\cos \left( {\theta + \frac{{2\pi }}{3}} \right)}},$ then $x + y + z = $

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