જો $\sin 6\theta = 32{\cos ^5}\theta \sin \theta - 32{\cos ^3}\theta \sin \theta + 3x,$ તો $x = $
$\cos \theta $
$\cos 2\theta $
$\sin \theta $
$\sin 2\theta $
$\frac{{3 + \cot \,7\,{6^ \circ }\,\cot \,{{16}^ \circ }}}{{\cot \,{{76}^ \circ } + \cot \,{{16}^ \circ }}}$ =
$cos^273^o + cos^247^o + (cos73^o . cos47^o )$ =
$1 - 2{\sin ^2}\left( {\frac{\pi }{4} + \theta } \right) = $
$\cos 20^\circ \cos 40^\circ \cos 80^\circ = $
જો $A$ એ તૃતીય ચરણમાં હોય અને $3\ tanA - 4 = 0$ થાય તો $5\ sin\ 2A + 3\ sinA + 4\ cosA$ =