જો $\sin 6\theta = 32{\cos ^5}\theta \sin \theta - 32{\cos ^3}\theta \sin \theta + 3x,$ તો $x = $
જો $\sin 6\theta = 32{\cos ^5}\theta \sin \theta - 32{\cos ^3}\theta \sin \theta + 3x,$ તો $x = $
- A
$\cos \theta $
- B
$\cos 2\theta $
- C
$\sin \theta $
- D
$\sin 2\theta $
Similar Questions
જો $cos A = {3\over 4} , $ તો $32\sin \left( {\frac{A}{2}} \right)\sin \left( {\frac{{5A}}{2}} \right) = $
જો $cos A = {3\over 4} , $ તો $32\sin \left( {\frac{A}{2}} \right)\sin \left( {\frac{{5A}}{2}} \right) = $
$1 + \cos \,{56^o} + \cos \,{58^o} - \cos {66^o} = $
$1 + \cos \,{56^o} + \cos \,{58^o} - \cos {66^o} = $
- [IIT 1964]
$\sqrt 2 + \sqrt 3 + \sqrt 4 + \sqrt 6 = . . ..$
$\sqrt 2 + \sqrt 3 + \sqrt 4 + \sqrt 6 = . . ..$
- [IIT 1975]
${\sin ^2}\frac{\pi }{8} + {\sin ^2}\frac{{3\pi }}{8} + {\sin ^2}\frac{{5\pi }}{8} + {\sin ^2}\frac{{7\pi }}{8}$ =
${\sin ^2}\frac{\pi }{8} + {\sin ^2}\frac{{3\pi }}{8} + {\sin ^2}\frac{{5\pi }}{8} + {\sin ^2}\frac{{7\pi }}{8}$ =
સમીકરણ $\frac{{\cos 6x + 6\cos 4x + 15\cos 2x + 10}}{{\cos 5x + 5\cos 3x + 10\cos x}}$ ની કિમત મેળવો.
સમીકરણ $\frac{{\cos 6x + 6\cos 4x + 15\cos 2x + 10}}{{\cos 5x + 5\cos 3x + 10\cos x}}$ ની કિમત મેળવો.