જો sin 6theta = 32{cos ^5}theta sin theta - 3 | vedclass

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Question

(d) $\sin 6	heta = 2\sin 3	heta \cos 3	heta $

$ = 2\,[3\sin 	heta - 4{\sin ^3}	heta ]\,[4{\cos ^3}	heta - 3\cos 	heta ]$ 

$=24 \sin

Vedclass · Accepted Answer

$\sin 2	heta $

Vedclass · Answer

(d) $\sin 6	heta = 2\sin 3	heta \cos 3	heta $

$ = 2\,[3\sin 	heta - 4{\sin ^3}	heta ]\,[4{\cos ^3}	heta - 3\cos 	heta ]$ 

$=24 \sin 	heta \cos 	heta (\sin ^2 	heta + \cos ^2 	heta) -18\sin 	heta \cos 	heta  -32 \sin ^2 	heta \cos^2 	heta$

$ = 32{\cos ^5}	heta \sin 	heta - 32{\cos ^3}	heta \sin 	heta + 3\sin 2	heta $ 

On comparing, $x = \sin 2	heta .$

જો $\sin 6\theta = 32{\cos ^5}\theta \sin \theta - 32{\cos ^3}\theta \sin \theta + 3x,$ તો $x = $

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