cos 15^circ - sin 15^circ = . . . | vedclass

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Question

(a) $\cos {15^o} - \sin {15^o} = \sqrt 2 \,.\cos \,({45^o} + {15^o}) $

$= \sqrt 2 \,.\,\cos \,\,{60^o}$

$ = \sqrt 2 \,.\frac{1}{2} = \frac{1}{{\

Vedclass · Accepted Answer

$\frac{1}{{\sqrt 2 }}$

Vedclass · Answer

(a) $\cos {15^o} - \sin {15^o} = \sqrt 2 \,.\cos \,({45^o} + {15^o}) $

$= \sqrt 2 \,.\,\cos \,\,{60^o}$

$ = \sqrt 2 \,.\frac{1}{2} = \frac{1}{{\sqrt 2 }}$.

$\cos 15^\circ - \sin 15^\circ = . . .$

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