If $\cos p\theta = \cos q\theta ,p \ne q$, then
If $\cos p\theta = \cos q\theta ,p \ne q$, then
- A
$\theta = 2n\pi $
- B
$\theta = \frac{{2n\pi }}{{p \pm q}}$
- C
$\theta = \frac{{n\pi }}{{p + q}}$
- D
None of these
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- [KVPY 2018]
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