If 5x - 12y + 10 = 0 and 12y - 5x + 16 = 0 are two tangents to a circle, then radius of circle is

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10-1.Circle and System of Circles

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If $5x - 12y + 10 = 0$ and $12y - 5x + 16 = 0$ are two tangents to a circle, then the radius of the circle is

A

$1$

B

$2$

C

$4$

D

$6$

Solution

(a) Given tangents are

$5x – 12y + 10 = 0,\,$ $5x – 12y – 16 = 0$

Radius $ = \frac{{{c_1} – {c_2}}}{{2\sqrt {{a^2} + {b^2}} }} $

$= \frac{{26}}{{2.13}} = 1$.

Standard 11

Mathematics

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