If f(x) = frac{x}{{x - 1}} , then frac{{f(a)}}{{f(a + 1)}} =

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1.Relation and Function

easy

If $f(x) = \frac{x}{{x - 1}}$, then $\frac{{f(a)}}{{f(a + 1)}} = $

A

$f( - a)$

B

$f\left( {\frac{1}{a}} \right)$

C

$f({a^2})$

D

$f\left( {\frac{{ - a}}{{a - 1}}} \right)$

Solution

(c) $\frac{{f(a)}}{{f\,(a + 1)}} = \frac{{a/(a – 1)}}{{(a + 1)/a}} $

$= \frac{{{a^2}}}{{{a^2} – 1}} = f({a^2})$.

Standard 12

Mathematics

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