1.Relation and Function
easy

If $f(x) = \frac{x}{{x - 1}} = \frac{1}{y}$, then $f(y) = $

A

$x$

B

$x + 1$

C

$x - 1$

D

$1 - x$

Solution

(d) $f(x) = \frac{x}{{x – 1}} = \frac{1}{y}\,\, $

$\Rightarrow \,\,\frac{{ – 1}}{{x – 1}} = \frac{{y – 1}}{y}$ {Applying dividendo}

$ \Rightarrow \,\,\frac{{x – 1}}{{ – 1}} = \frac{y}{{y – 1}}\, $

$\Rightarrow \,\, – x + 1 = f(y).$

Standard 12
Mathematics

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