Let f(x) = sin,x,,,g(x) = x.

Statement 1:& | vedclass

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Question

Let $f\left( x \right) = \sin \,x$ and $f\left( x \right) = \sin \,x$

Statement-$1$ : $f\left( x \right) \le gx\left( {\forall x} \right)

Vedclass · Accepted Answer

Statement $1$ is true, Statement $2$ is true,Statement $2$ is not a correct explanation for Statement $1.$

Vedclass · Answer

Let $f\left( x ight) = \sin \,x$ and $f\left( x ight) = \sin \,x$

Statement-$1$ : $f\left( x ight) \le gx\left( {\forall x} ight) \in \left( {0,\infty } ight)$

i.e, $\sin \,x \le x\forall x \in \left( {0,\infty } ight)$

which is true

Statement-$2$ : $f\left( x ight) \le 1\forall x \in \left( {0,\infty } ight)$

i.e., $\sin \,x \le 1\forall x \in \left( {0,\infty } ight)$

It is true and 

$g\left( x ight) = x 	o \infty $ as $x 	o \infty $ also true.

Let $f(x) = sin\,x,\,\,g(x) = x.$

Statement $1:$ $f(x)\, \le \,g\,(x)$ for $x$ in $(0,\infty )$

Statement $2:$ $f(x)\, \le \,1$ for $(x)$ in $(0,\infty )$ but $g(x)\,\to \infty$ as $x\,\to \infty$

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