Gujarati
14.Probability
easy

If $P(A) = \frac{1}{2},\,\,P(B) = \frac{1}{3}$ and $P(A \cap B) = \frac{7}{{12}},$ then the value of $P\,(A' \cap B')$ is

A

$\frac{7}{{12}}$

B

$\frac{3}{4}$

C

$\frac{1}{4}$

D

$\frac{1}{6}$

Solution

(b) $P(A' \cap B') = 1 – P(A \cup B)$

$ = 1 – \left( {\frac{1}{2} + \frac{1}{3} – \frac{7}{{12}}} \right) = 1 – \frac{1}{4} = \frac{3}{4}$.

Standard 11
Mathematics

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