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14.Probability
medium
यदि $P(A) = P(B) = x$ तथा $P(A \cap B) = P(A' \cap B') = \frac{1}{3}$ हो, तो $x = $
A
$\frac{1}{2}$
B
$\frac{1}{3}$
C
$\frac{1}{4}$
D
$\frac{1}{6}$
Solution
(a) $P(A' \cap B') = 1 – P(A \cup B) \Rightarrow \,P(A \cup \,B) = \frac{2}{3}$
अब $P(A \cup B)\, = P(A) + P(B) – P(A \cap B)$
$⇒ \frac{2}{3} = x + x – \frac{1}{3} \Rightarrow \,x = \frac{1}{2}$.
Standard 11
Mathematics