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1.Units, Dimensions and Measurement
medium
If $L$ and $R$ are respectively the inductance and resistance, then the dimensions of $\frac{R}{L}$ will be
A${T^2}$
B$T$
C${T^{ - 1}}$
D${T^{ - 2}}$
Solution
(c) $L/R$ is a time constant so $(R/L) = {T^{ – 1}}$
Standard 11
Physics
Similar Questions
Match List $I$ with List $II$ :
| List $I$ (Physical Quantity) | List $II$ (Dimensional Formula) |
| $(A)$ Pressure gradient | $(I)$ $\left[ M ^0 L ^2 T ^{-2}\right]$ |
| $(B)$ Energy density | $(II)$ $\left[ M ^1 L ^{-1} T ^{-2}\right]$ |
| $(C)$ Electric Field | $(III)$ $\left[ M ^1 L ^{-2} T ^{-2}\right]$ |
| $(D)$ Latent heat | $(IV)$ $\left[ M ^1 L ^1 T ^{-3} A ^{-1}\right]$ |
