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3-1.Vectors
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$A = 3\hat i + 4\hat j$ અને $B = 7\hat i + 24\hat j$ છે, $B$ ના મૂલ્ય જેટલો અને $A$ ને સમાંતર સદિશ મેળવો.
A
$5\hat i + 20\hat j$
B
$15\hat i + 10\hat j$
C
$20\hat i + 15\hat j$
D
$15\hat i + 20\hat j$
Solution
(d)$|B|\, = \sqrt {{7^2} + {{(24)}^2}} $ $ = \sqrt {625} $ $ = 25$
Unit vector in the direction of $A$ will be $\hat A = \frac{{3\hat i + 4\hat j}}{5}$
So required vector =$25\left( {\frac{{3\hat i + 4\hat j}}{5}} \right)\,$ $ = 15\hat i + 20\hat j$
Standard 11
Physics
