If 2 + i is a root of the equation {x^3} - 5{ | vedclass

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Question

(a) As the coefficients are real and one root is $2 + i,$ therefore, another root is $2 - i$ (conjugate of $2 + i$).

Let the third root be ? then s

Vedclass · Accepted Answer

$1$ and $2 - i$

Vedclass · Answer

(a) As the coefficients are real and one root is $2 + i,$ therefore, another root is $2 - i$ (conjugate of $2 + i$).

Let the third root be ? then sum of the roots $ = 2 + i + 2 - i + \alpha $

==> $ - ( - 5) = 4 + \alpha \Rightarrow \alpha = 1$

So, the other two roots are $2 - i$ and $1$.

If $2 + i$ is a root of the equation ${x^3} - 5{x^2} + 9x - 5 = 0$, then the other roots are

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