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3.Trigonometrical Ratios, Functions and Identities
medium
यदि $(\sec A + \tan A)\,(\sec B + \tan B)\,(\sec C + \tan C)$$ = \,(\sec A - \tan A)\,(\sec B - \tan B)\,(\sec C - \tan C),$ तब प्रत्येक पक्ष बराबर है
A
$1$
B
$-1$
C
$0$
D
$a$ ओर $b$ दोनो
Solution
(d) यदि $L = M$, तब ${L^2} = LM$ या $ML = {M^2}$
दोनों $LM = ML = 1$ चूँकि ${\sec ^2}A – {\tan ^2}A = 1$
$\therefore$ ${L^2} = {M^2} = 1$.
Standard 11
Mathematics
