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3.Trigonometrical Ratios, Functions and Identities
easy
$\sin 600^\circ \cos 330^\circ + \cos 120^\circ \sin 150^\circ $ का मान होगा
A
$-1$
B
$1$
C
$\frac{1}{{\sqrt 2 }}$
D
$\frac{{\sqrt 3 }}{2}$
Solution
(a) $\sin \,{600^o}\,\cos \,{330^o} + \cos \,{120^o}\,\sin \,{150^o}$
$ = – \sin \,{60^o}\,\cos \,{30^o} – \sin \,{30^o}\,\cos \,{60^o}$
$ = – \left\{ {\sin \,({{60}^o} + {{30}^o})} \right\} = – 1$.
Standard 11
Mathematics
