If frac{{cos x}}{a} = frac{{cos (x + theta )} | vedclass

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Question

Correct Answer - C

For each of the ratios be $1 / k$.

$\frac{a+c}{b+d}=\frac{k \cos x+k \cos (x+2 B)}{k \cos (x+	heta)+k \cos (x+3 	heta)}$

Vedclass · Accepted Answer

$\frac{b}{c}$

Vedclass · Answer

Correct Answer - C

For each of the ratios be $1 / k$.

$\frac{a+c}{b+d}=\frac{k \cos x+k \cos (x+2 B)}{k \cos (x+	heta)+k \cos (x+3 	heta)}$

$=\frac{2 \cos (x+	heta) \cos 	heta}{2 \cos (x+2 	heta) \cos 	heta}$

$=\frac{\cos (x+	heta)}{\cos (x+2 	heta)}=\frac{b}{c}$

If $\frac{{\cos x}}{a} = \frac{{\cos (x + \theta )}}{b} = \frac{{\cos (x + 2\theta )}}{c} = \frac{{\cos (x + 3\theta )}}{d} \, ,$ then $\left( {\frac{{a + c}}{{b + d}}} \right)$ is equal to :-

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