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1.Set Theory
normal
If $A$ and $B$ are any two non empty sets and $A$ is proper subset of $B$. If $n(A) = 4$, then minimum possible value of $n(A \Delta B)$ is (where $\Delta$ denotes symmetric difference of set $A$ and set $B$)
A
$2$
B
$1$
C
$0$
D
$4$
Solution
As $A \subset B \Rightarrow A-B=0$
$B-A \geq 1$
$n(A \Delta B)=n((A-B) \cup(B-A)) \geq 1$
minimum value $=1$
Standard 11
Mathematics