જો $cosA + cosB = cosC,\ sinA + sinB = sinC$ હોય તો સમીકરણ $\frac{{\sin \left( {A + B} \right)}}{{\sin 2C}}$ = 

  • A

    $0$

  • B

    $1$

  • C

    $2$

  • D

    $3$

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