3-1.Vectors
easy

यदि एक कण बिन्दु $P (2,3,5)$ से बिन्दु $Q (3,4,5) $ तक गति करता है, तो इसका विस्थापन सदिश होगा

A

$\hat i + \hat j + 10\hat k$

B

$\hat i + \hat j + 5\hat k$

C

$\hat i + \hat j$

D

$2\hat i + 4\hat j + 6\hat k$

Solution

(c) विस्थापन सदिश $\mathop r\limits^ \to = \Delta x\hat i + \Delta y\hat j + \Delta z\hat k$

$ = (3 – 2)\hat i + (4 – 3)\hat j + (5 – 5)\hat k$$ = \hat i + \hat j$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.