13.Nuclei
medium

If a radioactive substance reduces to $\frac{1}{{16}}$ of its original mass in $40$ days, what is its half-life .........$days$

A

$10$ 

B

$20$ 

C

$40$ 

D

None of these

(AIIMS-2003)

Solution

(a) $\frac{N}{{{N_0}}} = {\left( {\frac{1}{2}} \right)^n}$

==> $\frac{1}{{16}} = {\left( {\frac{1}{2}} \right)^4} = {\left( {\frac{1}{2}} \right)^n}$

==>$ n = 4.$

Also $n = \frac{t}{{{T_{1/2}}}}$

==> ${T_{1/2}} = \frac{{40}}{4} = 10\,days$

Standard 12
Physics

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