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13.Nuclei
medium
If a radioactive substance reduces to $\frac{1}{{16}}$ of its original mass in $40$ days, what is its half-life .........$days$
A
$10$
B
$20$
C
$40$
D
None of these
(AIIMS-2003)
Solution
(a) $\frac{N}{{{N_0}}} = {\left( {\frac{1}{2}} \right)^n}$
==> $\frac{1}{{16}} = {\left( {\frac{1}{2}} \right)^4} = {\left( {\frac{1}{2}} \right)^n}$
==>$ n = 4.$
Also $n = \frac{t}{{{T_{1/2}}}}$
==> ${T_{1/2}} = \frac{{40}}{4} = 10\,days$
Standard 12
Physics