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8.Electromagnetic waves
hard
If frequency of electromagnetic wave is $60 \mathrm{MHz}$ and it travels in air along $\mathrm{z}$ direction then the corresponding electric and magnetic field vectors will be mutually perpendicular to each other and the wavelength of the wave (in $\mathrm{m}$ ) is :
A
$2.5$
B
$10$
C
$5$
D
$2$
(JEE MAIN-2024)
Solution
$\lambda=\frac{\mathrm{c}}{\mathrm{f}}=\frac{3 \times 10^8}{60 \times 10^6}=5 \mathrm{~m}$
Standard 12
Physics