8.Electromagnetic waves
hard

If frequency of electromagnetic wave is $60 \mathrm{MHz}$ and it travels in air along $\mathrm{z}$ direction then the corresponding electric and magnetic field vectors will be mutually perpendicular to each other and the wavelength of the wave (in $\mathrm{m}$ ) is :

A

$2.5$

B

$10$

C

$5$

D

$2$

(JEE MAIN-2024)

Solution

$\lambda=\frac{\mathrm{c}}{\mathrm{f}}=\frac{3 \times 10^8}{60 \times 10^6}=5 \mathrm{~m}$

Standard 12
Physics

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