1.Units, Dimensions and Measurement
medium

જો દબાણ $P$, વેગ $V$ અને સમય $T$ ને મૂળભૂત ભૌતિક રાશિ તરીકે લેવામાં આવે છે તો બળનું પારિમાણિક સૂત્ર શું હશે ?

A

$P{V^2}{T^2}$

B

${P^{ - 1}}{V^2}{T^{ - 2}}$

C

$PV{T^2}$

D

${P^{ - 1}}V{T^2}$

Solution

$F\,\, = \,\,{P^\alpha }{v^\beta }{T^\gamma }$

$\left[ {{M^1}{L^1}{T^{ – 2}}} \right]\,\, = \,\,{\left[ {{M^1}{L^{ – 1}}{T^2}} \right]^\alpha }\,{\left[ {L{T^{ – 1}}} \right]^\beta }{\left[ T \right]^\gamma }$

$\,\,\left[ {{M^1}{L^1}{R^{ – 2}}} \right]\,\, = \,\,\left[ {{M^\alpha }{L^{ – \alpha \, + \;\beta }}{T^{ – 2\alpha  – \beta  + \gamma }}} \right]$

$\alpha \,\, = \,\,1\,;\,\, – \alpha \,\, + \;\,\beta \,\, = \,\,1\,$

$\beta \,\, = \,\,\,2,\,\,2 – 2\alpha \,\, – \,\,\beta \,\, + \;\,\gamma \,\, =  – 2$

$\therefore \,\, – 2\,\, – \,\,2\,\, + \;\,\gamma \,\, =  – 2\,\,$

$\,\gamma \,\, = \,\,2$

$ \Rightarrow \,\,F\,\, = \,\,P{v^2}{T^2}$

Standard 11
Physics

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