What is Dimensional Analysis ? State uses of Dimensional Analysis.
What is Dimensional Analysis ? State uses of Dimensional Analysis.
A method of obtaining the solution of certain problems in physics by using dimensional formula is called dimensional analysis.
Uses of Dimensional Analysis :
$(a)$ To obtain the relation between the units of some physical quantity in two different systems of units.
$(b)$ To check the dimensional consistency of an equation connecting different physical quantities.
$(c)$ To derive the equation for a physical quantity in terms of the other (related) physical quantities.
Similar Questions
The velocity of water waves $v$ may depend upon their wavelength $\lambda $, the density of water $\rho $ and the acceleration due to gravity $g$. The method of dimensions gives the relation between these quantities as
The velocity of water waves $v$ may depend upon their wavelength $\lambda $, the density of water $\rho $ and the acceleration due to gravity $g$. The method of dimensions gives the relation between these quantities as
In the relation $y = a\cos (\omega t - kx)$, the dimensional formula for $k$ is
In the relation $y = a\cos (\omega t - kx)$, the dimensional formula for $k$ is
The equation of stationary wave is
$\mathrm{y}=2 \mathrm{a} \sin \left(\frac{2 \pi \mathrm{nt}}{\lambda}\right) \cos \left(\frac{2 \pi \mathrm{x}}{\lambda}\right)$
Which of the following is NOT correct
The equation of stationary wave is
$\mathrm{y}=2 \mathrm{a} \sin \left(\frac{2 \pi \mathrm{nt}}{\lambda}\right) \cos \left(\frac{2 \pi \mathrm{x}}{\lambda}\right)$
Which of the following is NOT correct
- [JEE MAIN 2024]
The potential energy of a particle varies with distance $x$ from a fixed origin as $U=\frac{A \sqrt{x}}{x^2+B}$, where $A$ and $B$ are dimensional constants then dimensional formula for $A B$ is
The potential energy of a particle varies with distance $x$ from a fixed origin as $U=\frac{A \sqrt{x}}{x^2+B}$, where $A$ and $B$ are dimensional constants then dimensional formula for $A B$ is
If we use permittivity $ \varepsilon $, resistance $R$, gravitational constant $G$ and voltage $V$ as fundamental physical quantities, then
If we use permittivity $ \varepsilon $, resistance $R$, gravitational constant $G$ and voltage $V$ as fundamental physical quantities, then