If tangents are drawn from the point ($2 + 13cos\theta , 3 + 13sin\theta $) to the ellipse $\frac{(x-2)^2}{25} + \frac{(y-3)^2}{144} = 1,$ then angle between them, is

  • A

    $\frac{\pi }{6}$

  • B

    $\frac{\pi }{3}$

  • C

    $\frac{\pi }{2}$

  • D

    $\frac{2\pi }{3}$

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