6-2.Equilibrium-II (Ionic Equilibrium)
medium

यदि लेक्टिक अम्ल का $\mathrm{pKa}, 5$ है तो $25^{\circ} \mathrm{C}$ पर $0.005 \mathrm{M}$ केल्शियम लेक्टेट विलयन की $\mathrm{pH}$ $\times 10^{-1}$ है। (निकटतम पूर्णाक)

A

$85$

B

$84$

C

$83$

D

$82$

(JEE MAIN-2023)

Solution

Concentration of calcium lactate $=0.005\,M ,:$ concentration of lactate ion $=(2 \times 0.005)\,M$. Calcium lactate is a salt of weak acid $+$ strong base $\therefore$ Salt hydrolysis will take place.

$pH =7+\frac{1}{2}( pKa +\log C )$

$=7+\frac{1}{2}(5+\log (2 \times 0.005))$

$=7+\frac{1}{2}[5-2 \log 10]=7+\frac{1}{2} \times 3=8.5=85 \times 10^{-1}$

Standard 11
Chemistry

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