The degree of ionization of a $0.1 \,M$ bromoacetic acid solution is $0.132$ Calculate the $pH$ of the solution and the $p K_{ a }$ of bromoacetic acid.
Degree of ionization, $a=0.132$
Concentration, $c=0.1\, M$
Thus, the concentration of $H _{3} O ^{+}= c$. $a$
$=0.1 \times 0.132$
$=0.0132$
$pH =-\log \left[ H ^{+}\right]$
$=-\log (0.0132)$
$=1.879: 1.88$
Now,
$K_{a}=C \alpha^{2}$
$=0.1 \times(0.132)^{2}$
$K_{a}=.0017$
$p K_{a}=2.75$
The $K_a$ of monobasic acid $A, B$ and $C$ are $10^{-6}, 10^{-8}$ and $10^{-10}$ respectively. The concentrations of $A, B$ and $C$ are respectively. $0.1\,M$, $0.01\, M$ and $0.001\, M$. Which of the following is correct for $pOH$ of $A, B$ and $C$ ?
A weak acid is $ 0.1\% $ ionised in $0.1\, M $ solution. Its $pH$ is
What is the $pH$ of solution of $7$ $gm$ $N{H_4}OH$ per $500$ $mL$ ? ( ${K_b}$ of $N{H_4}OH 1.8 \times {10^{ - 5}}$, Molecular moles of $N{H_4}OH$ is $35\,g\,mo{l^{ - 1}}$ )
Which of the following base is weakest
${K_a}$ of $C{H_3}COOH$ is $1.76 \times {10^{ - 5}}$ at $298$ $K$ temperature. Calculate dissociation constant of its conjugate base.