The degree of ionization of a $0.1 \,M$ bromoacetic acid solution is $0.132$ Calculate the $pH$ of the solution and the $p K_{ a }$ of bromoacetic acid.

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Degree of ionization, $a=0.132$

Concentration, $c=0.1\, M$

Thus, the concentration of $H _{3} O ^{+}= c$. $a$

$=0.1 \times 0.132$

$=0.0132$

$pH =-\log \left[ H ^{+}\right]$

$=-\log (0.0132)$

$=1.879: 1.88$

Now,

$K_{a}=C \alpha^{2}$

$=0.1 \times(0.132)^{2}$

$K_{a}=.0017$

$p K_{a}=2.75$

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  • [IIT 2018]