The degree of ionization of a $0.1 \,M$ bromoacetic acid solution is $0.132$ Calculate the $pH$ of the solution and the $p K_{ a }$ of bromoacetic acid.
Degree of ionization, $a=0.132$
Concentration, $c=0.1\, M$
Thus, the concentration of $H _{3} O ^{+}= c$. $a$
$=0.1 \times 0.132$
$=0.0132$
$pH =-\log \left[ H ^{+}\right]$
$=-\log (0.0132)$
$=1.879: 1.88$
Now,
$K_{a}=C \alpha^{2}$
$=0.1 \times(0.132)^{2}$
$K_{a}=.0017$
$p K_{a}=2.75$
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