If the {p^{th}} term of an A.P. be q and {q^{ | vedclass

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Question

(b) Given that, ${T_p} = a + (p - 1)d = q$ &hellip;..$(i)$

and ${T_q} = a + (q - 1)d = p$ &hellip;.. $(ii)$

From $(i)$ and $(ii),$ we get $d = -

Vedclass · Accepted Answer

$p + q - r$

Vedclass · Answer

(b) Given that, ${T_p} = a + (p - 1)d = q$ &hellip;..$(i)$

and ${T_q} = a + (q - 1)d = p$ &hellip;.. $(ii)$

From $(i)$ and $(ii),$ we get $d = - \frac{{(p - q)}}{{(p - q)}} = - 1$

Putting value of $d$ in equation $(i),$ then $a = p + q - 1$

Now, ${r^{th}}$ term is given by $A.P.$

${T_r} = a + (r - 1)d = (p + q - 1) + (r - 1)( - 1)$ $ = p + q - r$

Note : Students should remember this question as a formula.

If the ${p^{th}}$ term of an $A.P.$ be $q$ and ${q^{th}}$ term be $p$, then its ${r^{th}}$ term will be

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