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8. Sequences and Series
easy
If the ${p^{th}}$ term of an $A.P.$ be $q$ and ${q^{th}}$ term be $p$, then its ${r^{th}}$ term will be
A
$p + q + r$
B
$p + q - r$
C
$p + r - q$
D
$p - q - r$
Solution
(b) Given that, ${T_p} = a + (p – 1)d = q$ …..$(i)$
and ${T_q} = a + (q – 1)d = p$ ….. $(ii)$
From $(i)$ and $(ii),$ we get $d = – \frac{{(p – q)}}{{(p – q)}} = – 1$
Putting value of $d$ in equation $(i),$ then $a = p + q – 1$
Now, ${r^{th}}$ term is given by $A.P.$
${T_r} = a + (r – 1)d = (p + q – 1) + (r – 1)( – 1)$ $ = p + q – r$
Note : Students should remember this question as a formula.
Standard 11
Mathematics