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8. Sequences and Series
easy
There are $15$ terms in an arithmetic progression. Its first term is $5$ and their sum is $390$. The middle term is
A
$23$
B
$26$
C
$29$
D
$32$
Solution
(b) According to the given condition
$\frac{{15}}{2}[10 + 14 \times d] = 390$
$ \Rightarrow $ $d = 3$
Hence middle term $i.e.$ ${8^{th}}$ term is given by
$5 + 7 \times 3 = 26$.
Standard 11
Mathematics