If the Boolean expression $\left( {p \oplus q} \right) \wedge \left( { \sim p\,\Theta\, q} \right)$ is equivalent to $p \wedge q$, where $ \oplus $ , $\Theta \in \left\{ { \wedge , \vee } \right\}$ , ,then the ordered pair $\left( { \oplus ,\Theta } \right)$ is
$\left( { \vee , \wedge } \right)$
$\left( { \vee , \vee } \right)$
$\left( { \wedge , \vee } \right)$
$\left( { \wedge , \wedge } \right)$
Consider the two statements :
$(\mathrm{S} 1):(\mathrm{p} \rightarrow \mathrm{q}) \vee(\sim \mathrm{q} \rightarrow \mathrm{p})$ is a tautology
$(S2): (\mathrm{p} \wedge \sim \mathrm{q}) \wedge(\sim \mathrm{p} \vee \mathrm{q})$ is a fallacy.
Then :
Statement$-I :$ $\sim (p\leftrightarrow q)$ is equivalent to $(p\wedge \sim q)\vee \sim (p\vee \sim q) .$
Statement$-II :$ $p\rightarrow (p\rightarrow q)$ is a tautology.
Negation of the compound proposition : If the examination is difficult, then I shall pass if I study hard
The conditional $(p \wedge q) ==> p$ is
The contrapositive of statement 'If Jaipur is capital of Rajasthan, then Jaipur is in India' is