If the centre of a circle is $(-6, 8)$ and it passes through the origin, then equation to its tangent at the origin, is
If the centre of a circle is $(-6, 8)$ and it passes through the origin, then equation to its tangent at the origin, is
- A
$2y = x$
- B
$4y = 3x$
- C
$3y = 4x$
- D
$3x + 4y = 0$
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- [IIT 1984]
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