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10-1.Circle and System of Circles
medium
If the centre of a circle is $(-6, 8)$ and it passes through the origin, then equation to its tangent at the origin, is
A
$2y = x$
B
$4y = 3x$
C
$3y = 4x$
D
$3x + 4y = 0$
Solution
(b) Centre $(-6, 8)$,
radius $ = \sqrt {{6^2} + {8^2}} = 10$
Equation of circle ${x^2} + {y^2} + 12x – 16y = 0$
Equation of tangent at $(0, 0)$ is $3x – 4y = 0$ .
Standard 11
Mathematics