Gujarati
10-1.Circle and System of Circles
medium

If the centre of a circle is $(-6, 8)$ and it passes through the origin, then equation to its tangent at the origin, is

A

$2y = x$

B

$4y = 3x$

C

$3y = 4x$

D

$3x + 4y = 0$

Solution

(b) Centre $(-6, 8)$,

radius $ = \sqrt {{6^2} + {8^2}} = 10$

Equation of circle ${x^2} + {y^2} + 12x – 16y = 0$

Equation of tangent at $(0, 0)$ is $3x – 4y = 0$ .

Standard 11
Mathematics

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