Let the tangents at the points $A (4,-11)$ and $B (8,-5)$ on the circle $x^2+y^2-3 x+10 y-15=0$, intersect at the point $C$. Then the radius of the circle, whose centre is $C$ and the line joining $A$ and $B$ is its tangent, is equal to

  • [JEE MAIN 2023]
  • A

    $\frac{3 \sqrt{3}}{4}$

  • B

    $2 \sqrt{13}$

  • C

    $\sqrt{13}$

  • D

    $\frac{2 \sqrt{13}}{3}$

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