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9.Straight Line
hard
If the line $3x + 3y -24 = 0$ intersects the $x-$ axis at the point $A$ and the $y-$ axis at the point $B$, then the incentre of the triangle $OAB$, where $O$ is the origin, is
A
$(3, 4)$
B
$(2, 2)$
C
$(4, 3)$
D
$(4, 4)$
(JEE MAIN-2019)
Solution

$I = \left( {\frac{{a{x_1} + b{x_2} + c{x_3}}}{{a + b + c}},\frac{{a{y_1} + b{y_2} + c{y_3}}}{{a + b + c}}} \right)$
$ = \left( {\frac{{8\left( {60} \right) + 6\left( 0 \right) + 10\left( 0 \right)}}{{24}},\frac{{10\left( 0 \right) + 6\left( 8 \right) + 8\left( 0 \right)}}{{24}}} \right) = \left( {2,2} \right)$
Standard 11
Mathematics