If the first term of an A.P. is 3 and the sum | vedclass

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Question

Sum of 1 st 25 terms $=$ sum of its next 15 termss

$\Rightarrow\left( T _{1}+\ldots \ldots+ T _{25}\right)=\left( T _{26}+\ldots . .+ T _{40}\right

Vedclass · Accepted Answer

$\frac{1}{6}$

Vedclass · Answer

Sum of 1 st 25 terms $=$ sum of its next 15 termss

$\Rightarrow\left( T _{1}+\ldots \ldots+ T _{25}ight)=\left( T _{26}+\ldots . .+ T _{40}ight)$

$\Rightarrow\left( T _{1}+\ldots . .+ T _{40}ight)=2\left( T _{1}+\ldots \ldots+ T _{25}ight)$

$\Rightarrow \frac{40}{2}[2 	imes 3+(39 d )]=2 	imes \frac{25}{2}[2 	imes 2+24 d ]$

$\Rightarrow d=\frac{1}{6}$

If the first term of an $A.P.$ is $3$ and the sum of its first $25$ terms is equal to the sum of its next $15$ terms, then the common difference of this $A.P.$ is :

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