1.Relation and Function
hard

यदि फलन $f : R -\{1 .-1\} \rightarrow A , f (x)=\frac{x^{2}}{1-x^{2}}$, द्वारा परिभाषित है तथा आच्छादी (surjective) है, तो $A$ बराबर है :

A

$R\, - \,[ - 1,0)$

B

$R\, - \,( - 1,0)$

C

$R\, - \,\{  - 1\} $

D

$[0,\infty )$

(JEE MAIN-2019)

Solution

$y\, = \frac{{{x^2}}}{{1 – {x^2}}}$

Range of $y : R – [ – 1,0)$ for surjective function, $A$ must be same as above range.

Standard 12
Mathematics

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