Gujarati
10-1.Circle and System of Circles
normal

If the line $y = mx + c$be a tangent to the circle ${x^2} + {y^2} = {a^2}$, then the point of contact is

A

$\left( {\frac{{ - {a^2}}}{c},{a^2}} \right)$

B

$\left( {\frac{{{a^2}}}{c},\frac{{ - {a^2}m}}{c}} \right)$

C

$\left( {\frac{{ - {a^2}m}}{c},\frac{{{a^2}}}{c}} \right)$

D

$\left( {\frac{{ - {a^2}c}}{m},\frac{{{a^2}}}{m}} \right)$

Solution

(c) Find points of intersection by simultaneously solving for $x$ and $y$ from $y = mx + c$ and ${x^2} + {y^2} = {a^2}$ which comes out as

$\left( { – \frac{{{a^2}m}}{c},\;\frac{{{a^2}}}{c}} \right)$.

Standard 11
Mathematics

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