If the line $y = mx + c$be a tangent to the circle ${x^2} + {y^2} = {a^2}$, then the point of contact is
$\left( {\frac{{ - {a^2}}}{c},{a^2}} \right)$
$\left( {\frac{{{a^2}}}{c},\frac{{ - {a^2}m}}{c}} \right)$
$\left( {\frac{{ - {a^2}m}}{c},\frac{{{a^2}}}{c}} \right)$
$\left( {\frac{{ - {a^2}c}}{m},\frac{{{a^2}}}{m}} \right)$
Let $O$ be the origin and $OP$ and $OQ$ be the tangents to the circle $x^2+y^2-6 x+4 y+8=0$ at the point $P$ and $Q$ on it. If the circumcircle of the triangle OPQ passes through the point $\left(\alpha, \frac{1}{2}\right)$, then a value of $\alpha$ is
The equation of circle which touches the axes of coordinates and the line $\frac{x}{3} + \frac{y}{4} = 1$ and whose centre lies in the first quadrant is ${x^2} + {y^2} - 2cx - 2cy + {c^2} = 0$, where $c$ is
Consider the following statements :
Assertion $(A)$ : The circle ${x^2} + {y^2} = 1$ has exactly two tangents parallel to the $x$ - axis
Reason $(R)$ : $\frac{{dy}}{{dx}} = 0$ on the circle exactly at the point $(0, \pm 1)$.
Of these statements
$S_1$ and $S_2$ are two concentric circles of radii $1$ and $2$ respectively. Two parallel tangents to $S_1$ cut off an arc from $S_2$. The length of the arc is
The line $y = x + c$will intersect the circle ${x^2} + {y^2} = 1$ in two coincident points, if