If the magnetic field in a plane electromagnetic wave is given by
$\overrightarrow{\mathrm{B}}=3 \times 10^{-8} \sin \left(1.6 \times 10^{3} \mathrm{x}+48 \times 10^{10} \mathrm{t}\right) \hat{\mathrm{j}}\; \mathrm{T}$
then what will be expression for electric field?
$\overrightarrow{\mathrm{E}}=\left(9 \sin \left(1.6 \times 10^{3} \mathrm{x}+48 \times 10^{10} \mathrm{t}\right) \hat{\mathrm{k}} \;\mathrm{V} / \mathrm{m}\right)$
$\left.\overrightarrow{\mathrm{E}}=\left(3 \times 10^{-8} \sin \left(1.6 \times 10^{3} \mathrm{x}+48 \times 10^{10} \mathrm{t}\right)\right) \hat{\mathrm{i}}\; \mathrm{V} / \mathrm{m}\right)$
$\overrightarrow{\mathrm{E}}=\left(60 \sin \left(1.6 \times 10^{3} \mathrm{x}+48 \times 10^{10} \mathrm{t}\right) \hat{\mathrm{k}}\; \mathrm{V} / \mathrm{m}\right)$
$\overrightarrow{\mathrm{E}}=\left(3 \times 10^{-8} \sin \left(1.6 \times 10^{3} \mathrm{x}+48 \times 10^{10} \mathrm{t}\right) \hat{\mathrm{j}} \;\mathrm{V} / \mathrm{m}\right)$
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$E_x=0, E_y=2.5 \frac{N}{C}\, cos\,\left[ {\left( {2\pi \;\times\;{{10}^6}\;\frac{{rad}}{s}\;\;} \right)t - \left( {\pi \;\times\;{{10}^{ - 2}}\;\frac{{rad}}{m}} \right)x} \right]$,and $ E_z=0$ . The wave is
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A point source of $e. m.$ radiation has an average power output of $800\,W$ . The maximum value of electric field at a distance $4.0\,m$ from the source is...$V/m$