If the ratio of the sum of first three terms | vedclass

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Question

(a) Here $\frac{{{S_3}}}{{{S_6}}} = \frac{{125}}{{152}}$

$\Rightarrow \frac{{a({r^3} - 1)/(r - 1)}}{{a({r^6} - 1)/(r - 1)}} = \frac{{125}}{{152}}$

Vedclass · Accepted Answer

$\frac{3}{5}$

Vedclass · Answer

(a) Here $\frac{{{S_3}}}{{{S_6}}} = \frac{{125}}{{152}}$

$\Rightarrow \frac{{a({r^3} - 1)/(r - 1)}}{{a({r^6} - 1)/(r - 1)}} = \frac{{125}}{{152}}$

$ \Rightarrow $$({r^3} - 1)152 = 125({r^6} - 1) $

$\Rightarrow {r^3} = \frac{{27}}{{125}}$

$\Rightarrow r = \frac{3}{5}$.

If the ratio of the sum of first three terms and the sum of first six terms of a $G.P.$ be $125 : 152$, then the common ratio r is

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