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8. Sequences and Series
easy
If the ratio of the sum of first three terms and the sum of first six terms of a $G.P.$ be $125 : 152$, then the common ratio r is
A
$\frac{3}{5}$
B
$\frac{5}{3}$
C
$\frac{2}{3}$
D
$\frac{3}{2}$
Solution
(a) Here $\frac{{{S_3}}}{{{S_6}}} = \frac{{125}}{{152}}$
$\Rightarrow \frac{{a({r^3} – 1)/(r – 1)}}{{a({r^6} – 1)/(r – 1)}} = \frac{{125}}{{152}}$
$ \Rightarrow $$({r^3} – 1)152 = 125({r^6} – 1) $
$\Rightarrow {r^3} = \frac{{27}}{{125}}$
$\Rightarrow r = \frac{3}{5}$.
Standard 11
Mathematics