If the speed of light (c), acceleration due t | vedclass

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Question

(b) Let $[G] \propto {c^x}{g^y}{p^z}$

by substituting the following dimensions :

$[G] = [{M^{ - 1}}{L^3}{T^{ - 2}}],\,[c] = [L{T^{ - 1}}],[g] =

Vedclass · Accepted Answer

${c^0}{g^2}{p^{ - 1}}$

Vedclass · Answer

(b) Let $[G] \propto {c^x}{g^y}{p^z}$

by substituting the following dimensions :

$[G] = [{M^{ - 1}}{L^3}{T^{ - 2}}],\,[c] = [L{T^{ - 1}}],[g] = [L{T^{ - 2}}]$

$[p] = [M{L^{ - 1}}{T^{ - 2}}]$

and by comparing the powers of both sides we can get $x = 0,\,y = 2,\,z = - 1$

$	herefore $ $[G] \propto {c^0}{g^2}{p^{ - 1}}$

If the speed of light $(c)$, acceleration due to gravity $(g)$ and pressure $(p)$ are taken as the fundamental quantities, then the dimension of gravitational constant is

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