If the straight line $4x + 3y + \lambda = 0$ touches the circle $2({x^2} + {y^2}) = 5$, then $\lambda $ is

  • A

    $\frac{{5\sqrt 5 }}{2}$

  • B

    $5\sqrt 2 $

  • C

    $\frac{{5\sqrt 5 }}{4}$

  • D

    $\frac{{5\sqrt {10} }}{2}$

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